PycURL 7.19.5.1

A straightforward and open source library that can be used for fetching objects identified by a URL within a Python based application

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What's new in PycURL 7.19.5.1:

  • Added CURLPROXY_SOCKS4A and CURLPROXY_SOCKS5_HOSTNAME.
  • setup.py now prints PycURL-specific option help when -h is used.
  • LibreSSL is now supported (patch by JiCiT.)
  • Fixed an oversight that broke PycURL building against libcurl 7.19.4 through 7.21.1. The bug was introduced in PycURL 7.19.5.
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LICENSE TYPE:
GPL 
FILE SIZE:
142 KB
USER RATING:
UNRATED
  0.0/5
DEVELOPED BY:
PycURL Team
CATEGORY:
Home \ Development \ Libraries
PycURL is a Python interface to libcurl that can be used to fetch objects identified by a URL from a Python program, similar to the urllib Python module. PycURL is mature, very fast, and supports a lot of features.

NOTE: PycURL is licensed and distributed under the terms of the GNU Library or Lesser General Public License (LGPL) and MIT License.

Last updated on July 14th, 2014

Runs on: Mac OS X (Universal Binary)

feature list requirements

#libcurl binding #url transfer #python library #libcurl #library #grabber #fetch

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